3(x+2)-12=(x+1)

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Solution for 3(x+2)-12=(x+1) equation: 



3(x+2)-12=(x+1)

We move all terms to the left:

3(x+2)-12-((x+1))=0

We multiply parentheses

3x-((x+1))+6-12=0



We calculate terms in parentheses: -((x+1)), so:

(x+1)

We get rid of parentheses

x+1

Back to the equation:

-(x+1)



We add all the numbers together, and all the variables

3x-(x+1)-6=0

We get rid of parentheses

3x-x-1-6=0

We add all the numbers together, and all the variables

2x-7=0

We move all terms containing x to the left, all other terms to the right

2x=7

x=7/2

x=3+1/2

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