3(x+2)-(x+11)=5(4-x)+2(x-5)

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Solution for 3(x+2)-(x+11)=5(4-x)+2(x-5) equation:



3(x+2)-(x+11)=5(4-x)+2(x-5)
We move all terms to the left:
3(x+2)-(x+11)-(5(4-x)+2(x-5))=0
We add all the numbers together, and all the variables
3(x+2)-(x+11)-(5(-1x+4)+2(x-5))=0
We multiply parentheses
3x-(x+11)-(5(-1x+4)+2(x-5))+6=0
We get rid of parentheses
3x-x-(5(-1x+4)+2(x-5))-11+6=0
We calculate terms in parentheses: -(5(-1x+4)+2(x-5)), so:
5(-1x+4)+2(x-5)
We multiply parentheses
-5x+2x+20-10
We add all the numbers together, and all the variables
-3x+10
Back to the equation:
-(-3x+10)
We add all the numbers together, and all the variables
2x-(-3x+10)-5=0
We get rid of parentheses
2x+3x-10-5=0
We add all the numbers together, and all the variables
5x-15=0
We move all terms containing x to the left, all other terms to the right
5x=15
x=15/5
x=3

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