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3(x+2)-(5x-4)=2(2x-1)
We move all terms to the left:
3(x+2)-(5x-4)-(2(2x-1))=0
We multiply parentheses
3x-(5x-4)-(2(2x-1))+6=0
We get rid of parentheses
3x-5x-(2(2x-1))+4+6=0
We calculate terms in parentheses: -(2(2x-1)), so:We add all the numbers together, and all the variables
2(2x-1)
We multiply parentheses
4x-2
Back to the equation:
-(4x-2)
-2x-(4x-2)+10=0
We get rid of parentheses
-2x-4x+2+10=0
We add all the numbers together, and all the variables
-6x+12=0
We move all terms containing x to the left, all other terms to the right
-6x=-12
x=-12/-6
x=+2
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