3(x+2)+x(x-3)=(x-1)(x-5)

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Solution for 3(x+2)+x(x-3)=(x-1)(x-5) equation: 



3(x+2)+x(x-3)=(x-1)(x-5)

We move all terms to the left:

3(x+2)+x(x-3)-((x-1)(x-5))=0

We multiply parentheses

x^2+3x-3x-((x-1)(x-5))+6=0

We multiply parentheses ..

x^2-((+x^2-5x-1x+5))+3x-3x+6=0



We calculate terms in parentheses: -((+x^2-5x-1x+5)), so:

(+x^2-5x-1x+5)

We get rid of parentheses

x^2-5x-1x+5

We add all the numbers together, and all the variables

x^2-6x+5

Back to the equation:

-(x^2-6x+5)



We add all the numbers together, and all the variables

x^2-(x^2-6x+5)+6=0

We get rid of parentheses

x^2-x^2+6x-5+6=0

We add all the numbers together, and all the variables

6x+1=0

We move all terms containing x to the left, all other terms to the right

6x=-1

x=-1/6

x=-1/6

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