3(x+2)+7(x+1)=12

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Solution for 3(x+2)+7(x+1)=12 equation:


Simplifying
3(x + 2) + 7(x + 1) = 12

Reorder the terms:
3(2 + x) + 7(x + 1) = 12
(2 * 3 + x * 3) + 7(x + 1) = 12
(6 + 3x) + 7(x + 1) = 12

Reorder the terms:
6 + 3x + 7(1 + x) = 12
6 + 3x + (1 * 7 + x * 7) = 12
6 + 3x + (7 + 7x) = 12

Reorder the terms:
6 + 7 + 3x + 7x = 12

Combine like terms: 6 + 7 = 13
13 + 3x + 7x = 12

Combine like terms: 3x + 7x = 10x
13 + 10x = 12

Solving
13 + 10x = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-13' to each side of the equation.
13 + -13 + 10x = 12 + -13

Combine like terms: 13 + -13 = 0
0 + 10x = 12 + -13
10x = 12 + -13

Combine like terms: 12 + -13 = -1
10x = -1

Divide each side by '10'.
x = -0.1

Simplifying
x = -0.1

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