3(x+2)+5=4x-3(x+1)

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Solution for 3(x+2)+5=4x-3(x+1) equation: 



3(x+2)+5=4x-3(x+1)

We move all terms to the left:

3(x+2)+5-(4x-3(x+1))=0

We multiply parentheses

3x-(4x-3(x+1))+6+5=0



We calculate terms in parentheses: -(4x-3(x+1)), so:

4x-3(x+1)

We multiply parentheses

4x-3x-3

We add all the numbers together, and all the variables

x-3

Back to the equation:

-(x-3)



We add all the numbers together, and all the variables

3x-(x-3)+11=0

We get rid of parentheses

3x-x+3+11=0

We add all the numbers together, and all the variables

2x+14=0

We move all terms containing x to the left, all other terms to the right

2x=-14

x=-14/2

x=-7

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