3(x+2)+5=2-4(2x+1)

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Solution for 3(x+2)+5=2-4(2x+1) equation: 



3(x+2)+5=2-4(2x+1)

We move all terms to the left:

3(x+2)+5-(2-4(2x+1))=0

We multiply parentheses

3x-(2-4(2x+1))+6+5=0



We calculate terms in parentheses: -(2-4(2x+1)), so:

2-4(2x+1)

determiningTheFunctionDomain
-4(2x+1)+2

We multiply parentheses

-8x-4+2

We add all the numbers together, and all the variables

-8x-2

Back to the equation:

-(-8x-2)



We add all the numbers together, and all the variables

3x-(-8x-2)+11=0

We get rid of parentheses

3x+8x+2+11=0

We add all the numbers together, and all the variables

11x+13=0

We move all terms containing x to the left, all other terms to the right

11x=-13

x=-13/11

x=-1+2/11

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