3(x+2)+5(x+1)=35

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Solution for 3(x+2)+5(x+1)=35 equation: 


Simplifying
3(x + 2) + 5(x + 1) = 35

Reorder the terms:
3(2 + x) + 5(x + 1) = 35
(2 * 3 + x * 3) + 5(x + 1) = 35
(6 + 3x) + 5(x + 1) = 35

Reorder the terms:
6 + 3x + 5(1 + x) = 35
6 + 3x + (1 * 5 + x * 5) = 35
6 + 3x + (5 + 5x) = 35

Reorder the terms:
6 + 5 + 3x + 5x = 35

Combine like terms: 6 + 5 = 11
11 + 3x + 5x = 35

Combine like terms: 3x + 5x = 8x
11 + 8x = 35

Solving
11 + 8x = 35

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + 8x = 35 + -11

Combine like terms: 11 + -11 = 0
0 + 8x = 35 + -11
8x = 35 + -11

Combine like terms: 35 + -11 = 24
8x = 24

Divide each side by '8'.
x = 3

Simplifying
x = 3

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