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3(x+2)+4(x+5)=2(x-1)+3x+14
We move all terms to the left:
3(x+2)+4(x+5)-(2(x-1)+3x+14)=0
We multiply parentheses
3x+4x-(2(x-1)+3x+14)+6+20=0
We calculate terms in parentheses: -(2(x-1)+3x+14), so:We add all the numbers together, and all the variables
2(x-1)+3x+14
We add all the numbers together, and all the variables
3x+2(x-1)+14
We multiply parentheses
3x+2x-2+14
We add all the numbers together, and all the variables
5x+12
Back to the equation:
-(5x+12)
7x-(5x+12)+26=0
We get rid of parentheses
7x-5x-12+26=0
We add all the numbers together, and all the variables
2x+14=0
We move all terms containing x to the left, all other terms to the right
2x=-14
x=-14/2
x=-7
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