3(x+2)+4(2x-2)=20

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Solution for 3(x+2)+4(2x-2)=20 equation: 



3(x+2)+4(2x-2)=20

We move all terms to the left:

3(x+2)+4(2x-2)-(20)=0

We multiply parentheses

3x+8x+6-8-20=0

We add all the numbers together, and all the variables

11x-22=0

We move all terms containing x to the left, all other terms to the right

11x=22

x=22/11

x=2

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