3(x+2)+3x=4(4+4x)

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Solution for 3(x+2)+3x=4(4+4x) equation: 



3(x+2)+3x=4(4+4x)

We move all terms to the left:

3(x+2)+3x-(4(4+4x))=0

We add all the numbers together, and all the variables

3(x+2)+3x-(4(4x+4))=0

We add all the numbers together, and all the variables

3x+3(x+2)-(4(4x+4))=0

We multiply parentheses

3x+3x-(4(4x+4))+6=0



We calculate terms in parentheses: -(4(4x+4)), so:

4(4x+4)

We multiply parentheses

16x+16

Back to the equation:

-(16x+16)



We add all the numbers together, and all the variables

6x-(16x+16)+6=0

We get rid of parentheses

6x-16x-16+6=0

We add all the numbers together, and all the variables

-10x-10=0

We move all terms containing x to the left, all other terms to the right

-10x=10

x=10/-10

x=-1

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