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3(x+2)+3=2-(1-3x)
We move all terms to the left:
3(x+2)+3-(2-(1-3x))=0
We add all the numbers together, and all the variables
3(x+2)-(2-(-3x+1))+3=0
We multiply parentheses
3x-(2-(-3x+1))+6+3=0
We calculate terms in parentheses: -(2-(-3x+1)), so:We add all the numbers together, and all the variables
2-(-3x+1)
determiningTheFunctionDomain -(-3x+1)+2
We get rid of parentheses
3x-1+2
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
3x-(3x+1)+9=0
We get rid of parentheses
3x-3x-1+9=0
We add all the numbers together, and all the variables
8!=0
There is no solution for this equation
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