3(x+2)+2x=7(x-1)+

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Solution for 3(x+2)+2x=7(x-1)+ equation: 



3(x+2)+2x=7(x-1)+

We move all terms to the left:

3(x+2)+2x-(7(x-1)+)=0

We add all the numbers together, and all the variables

2x+3(x+2)-(7(x-1)+)=0

We multiply parentheses

2x+3x-(7(x-1)+)+6=0



We calculate terms in parentheses: -(7(x-1)+), so:

7(x-1)+

We add all the numbers together, and all the variables

7(x-1)

We multiply parentheses

7x-7

Back to the equation:

-(7x-7)



We add all the numbers together, and all the variables

5x-(7x-7)+6=0

We get rid of parentheses

5x-7x+7+6=0

We add all the numbers together, and all the variables

-2x+13=0

We move all terms containing x to the left, all other terms to the right

-2x=-13

x=-13/-2

x=6+1/2

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