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3(x+2)+2=6x-3(-1+x)
We move all terms to the left:
3(x+2)+2-(6x-3(-1+x))=0
We add all the numbers together, and all the variables
3(x+2)-(6x-3(x-1))+2=0
We multiply parentheses
3x-(6x-3(x-1))+6+2=0
We calculate terms in parentheses: -(6x-3(x-1)), so:We add all the numbers together, and all the variables
6x-3(x-1)
We multiply parentheses
6x-3x+3
We add all the numbers together, and all the variables
3x+3
Back to the equation:
-(3x+3)
3x-(3x+3)+8=0
We get rid of parentheses
3x-3x-3+8=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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