3(x+2)+2(x-4)=x-3(x+2)

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Solution for 3(x+2)+2(x-4)=x-3(x+2) equation: 



3(x+2)+2(x-4)=x-3(x+2)

We move all terms to the left:

3(x+2)+2(x-4)-(x-3(x+2))=0

We multiply parentheses

3x+2x-(x-3(x+2))+6-8=0



We calculate terms in parentheses: -(x-3(x+2)), so:

x-3(x+2)

We multiply parentheses

x-3x-6

We add all the numbers together, and all the variables

-2x-6

Back to the equation:

-(-2x-6)



We add all the numbers together, and all the variables

5x-(-2x-6)-2=0

We get rid of parentheses

5x+2x+6-2=0

We add all the numbers together, and all the variables

7x+4=0

We move all terms containing x to the left, all other terms to the right

7x=-4

x=-4/7

x=-4/7

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