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3(x+2)+2(x-3)=4x+12
We move all terms to the left:
3(x+2)+2(x-3)-(4x+12)=0
We multiply parentheses
3x+2x-(4x+12)+6-6=0
We get rid of parentheses
3x+2x-4x-12+6-6=0
We add all the numbers together, and all the variables
x-12=0
We move all terms containing x to the left, all other terms to the right
x=12
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