3(x+2)+2(x+1)=5(x-3)

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Solution for 3(x+2)+2(x+1)=5(x-3) equation:


Simplifying
3(x + 2) + 2(x + 1) = 5(x + -3)

Reorder the terms:
3(2 + x) + 2(x + 1) = 5(x + -3)
(2 * 3 + x * 3) + 2(x + 1) = 5(x + -3)
(6 + 3x) + 2(x + 1) = 5(x + -3)

Reorder the terms:
6 + 3x + 2(1 + x) = 5(x + -3)
6 + 3x + (1 * 2 + x * 2) = 5(x + -3)
6 + 3x + (2 + 2x) = 5(x + -3)

Reorder the terms:
6 + 2 + 3x + 2x = 5(x + -3)

Combine like terms: 6 + 2 = 8
8 + 3x + 2x = 5(x + -3)

Combine like terms: 3x + 2x = 5x
8 + 5x = 5(x + -3)

Reorder the terms:
8 + 5x = 5(-3 + x)
8 + 5x = (-3 * 5 + x * 5)
8 + 5x = (-15 + 5x)

Add '-5x' to each side of the equation.
8 + 5x + -5x = -15 + 5x + -5x

Combine like terms: 5x + -5x = 0
8 + 0 = -15 + 5x + -5x
8 = -15 + 5x + -5x

Combine like terms: 5x + -5x = 0
8 = -15 + 0
8 = -15

Solving
8 = -15

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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