3(x+2)+2(x+1)=3(x-1)+x

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Solution for 3(x+2)+2(x+1)=3(x-1)+x equation: 



3(x+2)+2(x+1)=3(x-1)+x

We move all terms to the left:

3(x+2)+2(x+1)-(3(x-1)+x)=0

We multiply parentheses

3x+2x-(3(x-1)+x)+6+2=0



We calculate terms in parentheses: -(3(x-1)+x), so:

3(x-1)+x

We add all the numbers together, and all the variables

x+3(x-1)

We multiply parentheses

x+3x-3

We add all the numbers together, and all the variables

4x-3

Back to the equation:

-(4x-3)



We add all the numbers together, and all the variables

5x-(4x-3)+8=0

We get rid of parentheses

5x-4x+3+8=0

We add all the numbers together, and all the variables

x+11=0

We move all terms containing x to the left, all other terms to the right

x=-11

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