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3(x+2)(x-9)=0
We multiply parentheses ..
3(+x^2-9x+2x-18)=0
We multiply parentheses
3x^2-27x+6x-54=0
We add all the numbers together, and all the variables
3x^2-21x-54=0
a = 3; b = -21; c = -54;
Δ = b2-4ac
Δ = -212-4·3·(-54)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-33}{2*3}=\frac{-12}{6} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+33}{2*3}=\frac{54}{6} =9 $
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