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3(x+15)=2/3x-15
We move all terms to the left:
3(x+15)-(2/3x-15)=0
Domain of the equation: 3x-15)!=0We multiply parentheses
x∈R
3x-(2/3x-15)+45=0
We get rid of parentheses
3x-2/3x+15+45=0
We multiply all the terms by the denominator
3x*3x+15*3x+45*3x-2=0
Wy multiply elements
9x^2+45x+135x-2=0
We add all the numbers together, and all the variables
9x^2+180x-2=0
a = 9; b = 180; c = -2;
Δ = b2-4ac
Δ = 1802-4·9·(-2)
Δ = 32472
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32472}=\sqrt{36*902}=\sqrt{36}*\sqrt{902}=6\sqrt{902}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-6\sqrt{902}}{2*9}=\frac{-180-6\sqrt{902}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+6\sqrt{902}}{2*9}=\frac{-180+6\sqrt{902}}{18} $
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