3(x+12)+4x=10x+5(2x+2)

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Solution for 3(x+12)+4x=10x+5(2x+2) equation: 



3(x+12)+4x=10x+5(2x+2)

We move all terms to the left:

3(x+12)+4x-(10x+5(2x+2))=0

We add all the numbers together, and all the variables

4x+3(x+12)-(10x+5(2x+2))=0

We multiply parentheses

4x+3x-(10x+5(2x+2))+36=0



We calculate terms in parentheses: -(10x+5(2x+2)), so:

10x+5(2x+2)

We multiply parentheses

10x+10x+10

We add all the numbers together, and all the variables

20x+10

Back to the equation:

-(20x+10)



We add all the numbers together, and all the variables

7x-(20x+10)+36=0

We get rid of parentheses

7x-20x-10+36=0

We add all the numbers together, and all the variables

-13x+26=0

We move all terms containing x to the left, all other terms to the right

-13x=-26

x=-26/-13

x=+2

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