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3(x+1)=8(x-1/4)
We move all terms to the left:
3(x+1)-(8(x-1/4))=0
We add all the numbers together, and all the variables
3(x+1)-(8(+x-1/4))=0
We multiply parentheses
3x-(8(+x-1/4))+3=0
We multiply all the terms by the denominator
3x*4))-(8(+x-1+3*4))=0
We add all the numbers together, and all the variables
3x*4))-(8(x+11))=0
We add all the numbers together, and all the variables
3x*4))-(8(x=0
Wy multiply elements
12x^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{24}=0$
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