3(x+1)=6(x-2)

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Solution for 3(x+1)=6(x-2) equation: 



3(x+1)=6(x-2)

We move all terms to the left:

3(x+1)-(6(x-2))=0

We multiply parentheses

3x-(6(x-2))+3=0



We calculate terms in parentheses: -(6(x-2)), so:

6(x-2)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We get rid of parentheses

3x-6x+12+3=0

We add all the numbers together, and all the variables

-3x+15=0

We move all terms containing x to the left, all other terms to the right

-3x=-15

x=-15/-3

x=+5

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