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3(x+1)=5x+3(2x-1)
We move all terms to the left:
3(x+1)-(5x+3(2x-1))=0
We multiply parentheses
3x-(5x+3(2x-1))+3=0
We calculate terms in parentheses: -(5x+3(2x-1)), so:We get rid of parentheses
5x+3(2x-1)
We multiply parentheses
5x+6x-3
We add all the numbers together, and all the variables
11x-3
Back to the equation:
-(11x-3)
3x-11x+3+3=0
We add all the numbers together, and all the variables
-8x+6=0
We move all terms containing x to the left, all other terms to the right
-8x=-6
x=-6/-8
x=3/4
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