3(x+1)=3+2(x-1)

Solution for 3(x+1)=3+2(x-1) equation:

3(x+1)=3+2(x-1)

We move all terms to the left:

3(x+1)-(3+2(x-1))=0

We multiply parentheses

3x-(3+2(x-1))+3=0


We calculate terms in parentheses: -(3+2(x-1)), so:

3+2(x-1)

determiningTheFunctionDomain
2(x-1)+3

We multiply parentheses

2x-2+3

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)


We get rid of parentheses

3x-2x-1+3=0

We add all the numbers together, and all the variables

x+2=0

We move all terms containing x to the left, all other terms to the right

x=-2