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3(x+1)=2x+19
We move all terms to the left:
3(x+1)-(2x+19)=0
We multiply parentheses
3x-(2x+19)+3=0
We get rid of parentheses
3x-2x-19+3=0
We add all the numbers together, and all the variables
x-16=0
We move all terms containing x to the left, all other terms to the right
x=16
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