3(x+1)=2-(x-1)-4

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Solution for 3(x+1)=2-(x-1)-4 equation: 



3(x+1)=2-(x-1)-4

We move all terms to the left:

3(x+1)-(2-(x-1)-4)=0

We multiply parentheses

3x-(2-(x-1)-4)+3=0



We calculate terms in parentheses: -(2-(x-1)-4), so:

2-(x-1)-4

determiningTheFunctionDomain
-(x-1)+2-4

We add all the numbers together, and all the variables

-(x-1)-2

We get rid of parentheses

-x+1-2

We add all the numbers together, and all the variables

-1x-1

Back to the equation:

-(-1x-1)



We get rid of parentheses

3x+1x+1+3=0

We add all the numbers together, and all the variables

4x+4=0

We move all terms containing x to the left, all other terms to the right

4x=-4

x=-4/4

x=-1

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