3(x+1)=2(x-3/2)

Solution for 3(x+1)=2(x-3/2) equation:

3(x+1)=2(x-3/2)

We move all terms to the left:

3(x+1)-(2(x-3/2))=0

We add all the numbers together, and all the variables

3(x+1)-(2(+x-3/2))=0

We multiply parentheses

3x-(2(+x-3/2))+3=0

We multiply all the terms by the denominator


3x*2))-(2(+x-3+3*2))=0

We add all the numbers together, and all the variables

3x*2))-(2(x+3))=0

We add all the numbers together, and all the variables

3x*2))-(2(x=0

Wy multiply elements

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$