3(x+1)=(x+2)+3

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Solution for 3(x+1)=(x+2)+3 equation: 



3(x+1)=(x+2)+3

We move all terms to the left:

3(x+1)-((x+2)+3)=0

We multiply parentheses

3x-((x+2)+3)+3=0



We calculate terms in parentheses: -((x+2)+3), so:

(x+2)+3

We get rid of parentheses

x+2+3

We add all the numbers together, and all the variables

x+5

Back to the equation:

-(x+5)



We get rid of parentheses

3x-x-5+3=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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