3(x+1)=(7x-2)-3

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Solution for 3(x+1)=(7x-2)-3 equation: 



3(x+1)=(7x-2)-3

We move all terms to the left:

3(x+1)-((7x-2)-3)=0

We multiply parentheses

3x-((7x-2)-3)+3=0



We calculate terms in parentheses: -((7x-2)-3), so:

(7x-2)-3

We get rid of parentheses

7x-2-3

We add all the numbers together, and all the variables

7x-5

Back to the equation:

-(7x-5)



We get rid of parentheses

3x-7x+5+3=0

We add all the numbers together, and all the variables

-4x+8=0

We move all terms containing x to the left, all other terms to the right

-4x=-8

x=-8/-4

x=+2

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