3(x+1)5x=43

Solution for 3(x+1)5x=43 equation:

3(x+1)5x=43

We move all terms to the left:

3(x+1)5x-(43)=0

We multiply parentheses

15x^2+15x-43=0

a = 15; b = 15; c = -43;
Δ = b2-4ac
Δ = 152-4·15·(-43)
Δ = 2805
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{2805}}{2*15}=\frac{-15-\sqrt{2805}}{30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{2805}}{2*15}=\frac{-15+\sqrt{2805}}{30}
$