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3(x+1)/3=2x-5
We move all terms to the left:
3(x+1)/3-(2x-5)=0
We get rid of parentheses
3(x+1)/3-2x+5=0
We multiply all the terms by the denominator
3(x+1)-2x*3+5*3=0
We add all the numbers together, and all the variables
3(x+1)-2x*3+15=0
We multiply parentheses
3x-2x*3+3+15=0
Wy multiply elements
3x-6x+3+15=0
We add all the numbers together, and all the variables
-3x+18=0
We move all terms containing x to the left, all other terms to the right
-3x=-18
x=-18/-3
x=+6
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