3(x+1)-2x=3(x+1)-2x=x-(2+3(3-x))=x-(2+3(3-x))

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Solution for 3(x+1)-2x=3(x+1)-2x=x-(2+3(3-x))=x-(2+3(3-x)) equation: 



3(x+1)-2x=3(x+1)-2x=x-(2+3(3-x))=x-(2+3(3-x))

We move all terms to the left:

3(x+1)-2x-(3(x+1)-2x)=0

We add all the numbers together, and all the variables

-2x+3(x+1)-(3(x+1)-2x)=0

We multiply parentheses

-2x+3x-(3(x+1)-2x)+3=0



We calculate terms in parentheses: -(3(x+1)-2x), so:

3(x+1)-2x

We add all the numbers together, and all the variables

-2x+3(x+1)

We multiply parentheses

-2x+3x+3

We add all the numbers together, and all the variables

x+3

Back to the equation:

-(x+3)



We add all the numbers together, and all the variables

x-(x+3)+3=0

We get rid of parentheses

x-x-3+3=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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