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3(x+1)-2=-(x+5)
We move all terms to the left:
3(x+1)-2-(-(x+5))=0
We multiply parentheses
3x-(-(x+5))+3-2=0
We calculate terms in parentheses: -(-(x+5)), so:We add all the numbers together, and all the variables
-(x+5)
We get rid of parentheses
-x-5
We add all the numbers together, and all the variables
-1x-5
Back to the equation:
-(-1x-5)
3x-(-1x-5)+1=0
We get rid of parentheses
3x+1x+5+1=0
We add all the numbers together, and all the variables
4x+6=0
We move all terms containing x to the left, all other terms to the right
4x=-6
x=-6/4
x=-1+1/2
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