3(x+1)-2(3x-2)=13

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Solution for 3(x+1)-2(3x-2)=13 equation: 



3(x+1)-2(3x-2)=13

We move all terms to the left:

3(x+1)-2(3x-2)-(13)=0

We multiply parentheses

3x-6x+3+4-13=0

We add all the numbers together, and all the variables

-3x-6=0

We move all terms containing x to the left, all other terms to the right

-3x=6

x=6/-3

x=-2

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