3(x+1)-(x+2)=7(2x-5)

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Solution for 3(x+1)-(x+2)=7(2x-5) equation:


Simplifying
3(x + 1) + -1(x + 2) = 7(2x + -5)

Reorder the terms:
3(1 + x) + -1(x + 2) = 7(2x + -5)
(1 * 3 + x * 3) + -1(x + 2) = 7(2x + -5)
(3 + 3x) + -1(x + 2) = 7(2x + -5)

Reorder the terms:
3 + 3x + -1(2 + x) = 7(2x + -5)
3 + 3x + (2 * -1 + x * -1) = 7(2x + -5)
3 + 3x + (-2 + -1x) = 7(2x + -5)

Reorder the terms:
3 + -2 + 3x + -1x = 7(2x + -5)

Combine like terms: 3 + -2 = 1
1 + 3x + -1x = 7(2x + -5)

Combine like terms: 3x + -1x = 2x
1 + 2x = 7(2x + -5)

Reorder the terms:
1 + 2x = 7(-5 + 2x)
1 + 2x = (-5 * 7 + 2x * 7)
1 + 2x = (-35 + 14x)

Solving
1 + 2x = -35 + 14x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-14x' to each side of the equation.
1 + 2x + -14x = -35 + 14x + -14x

Combine like terms: 2x + -14x = -12x
1 + -12x = -35 + 14x + -14x

Combine like terms: 14x + -14x = 0
1 + -12x = -35 + 0
1 + -12x = -35

Add '-1' to each side of the equation.
1 + -1 + -12x = -35 + -1

Combine like terms: 1 + -1 = 0
0 + -12x = -35 + -1
-12x = -35 + -1

Combine like terms: -35 + -1 = -36
-12x = -36

Divide each side by '-12'.
x = 3

Simplifying
x = 3

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