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3(x+1)+x=2(x+10)+3
We move all terms to the left:
3(x+1)+x-(2(x+10)+3)=0
We add all the numbers together, and all the variables
x+3(x+1)-(2(x+10)+3)=0
We multiply parentheses
x+3x-(2(x+10)+3)+3=0
We calculate terms in parentheses: -(2(x+10)+3), so:We add all the numbers together, and all the variables
2(x+10)+3
We multiply parentheses
2x+20+3
We add all the numbers together, and all the variables
2x+23
Back to the equation:
-(2x+23)
4x-(2x+23)+3=0
We get rid of parentheses
4x-2x-23+3=0
We add all the numbers together, and all the variables
2x-20=0
We move all terms containing x to the left, all other terms to the right
2x=20
x=20/2
x=10
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