3(x+1)+x+1=2x+8

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Solution for 3(x+1)+x+1=2x+8 equation:


Simplifying
3(x + 1) + x + 1 = 2x + 8

Reorder the terms:
3(1 + x) + x + 1 = 2x + 8
(1 * 3 + x * 3) + x + 1 = 2x + 8
(3 + 3x) + x + 1 = 2x + 8

Reorder the terms:
3 + 1 + 3x + x = 2x + 8

Combine like terms: 3 + 1 = 4
4 + 3x + x = 2x + 8

Combine like terms: 3x + x = 4x
4 + 4x = 2x + 8

Reorder the terms:
4 + 4x = 8 + 2x

Solving
4 + 4x = 8 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
4 + 4x + -2x = 8 + 2x + -2x

Combine like terms: 4x + -2x = 2x
4 + 2x = 8 + 2x + -2x

Combine like terms: 2x + -2x = 0
4 + 2x = 8 + 0
4 + 2x = 8

Add '-4' to each side of the equation.
4 + -4 + 2x = 8 + -4

Combine like terms: 4 + -4 = 0
0 + 2x = 8 + -4
2x = 8 + -4

Combine like terms: 8 + -4 = 4
2x = 4

Divide each side by '2'.
x = 2

Simplifying
x = 2

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