3(x+1)+8=2(x+3)+x+5

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Solution for 3(x+1)+8=2(x+3)+x+5 equation: 


Simplifying
3(x + 1) + 8 = 2(x + 3) + x + 5

Reorder the terms:
3(1 + x) + 8 = 2(x + 3) + x + 5
(1 * 3 + x * 3) + 8 = 2(x + 3) + x + 5
(3 + 3x) + 8 = 2(x + 3) + x + 5

Reorder the terms:
3 + 8 + 3x = 2(x + 3) + x + 5

Combine like terms: 3 + 8 = 11
11 + 3x = 2(x + 3) + x + 5

Reorder the terms:
11 + 3x = 2(3 + x) + x + 5
11 + 3x = (3 * 2 + x * 2) + x + 5
11 + 3x = (6 + 2x) + x + 5

Reorder the terms:
11 + 3x = 6 + 5 + 2x + x

Combine like terms: 6 + 5 = 11
11 + 3x = 11 + 2x + x

Combine like terms: 2x + x = 3x
11 + 3x = 11 + 3x

Add '-11' to each side of the equation.
11 + -11 + 3x = 11 + -11 + 3x

Combine like terms: 11 + -11 = 0
0 + 3x = 11 + -11 + 3x
3x = 11 + -11 + 3x

Combine like terms: 11 + -11 = 0
3x = 0 + 3x
3x = 3x

Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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