3(x+1)+8=10-2(x+6)

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Solution for 3(x+1)+8=10-2(x+6) equation: 



3(x+1)+8=10-2(x+6)

We move all terms to the left:

3(x+1)+8-(10-2(x+6))=0

We multiply parentheses

3x-(10-2(x+6))+3+8=0



We calculate terms in parentheses: -(10-2(x+6)), so:

10-2(x+6)

determiningTheFunctionDomain
-2(x+6)+10

We multiply parentheses

-2x-12+10

We add all the numbers together, and all the variables

-2x-2

Back to the equation:

-(-2x-2)



We add all the numbers together, and all the variables

3x-(-2x-2)+11=0

We get rid of parentheses

3x+2x+2+11=0

We add all the numbers together, and all the variables

5x+13=0

We move all terms containing x to the left, all other terms to the right

5x=-13

x=-13/5

x=-2+3/5

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