3(x+1)+5=4(x-3)-2(2x-3)

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Solution for 3(x+1)+5=4(x-3)-2(2x-3) equation: 



3(x+1)+5=4(x-3)-2(2x-3)

We move all terms to the left:

3(x+1)+5-(4(x-3)-2(2x-3))=0

We multiply parentheses

3x-(4(x-3)-2(2x-3))+3+5=0



We calculate terms in parentheses: -(4(x-3)-2(2x-3)), so:

4(x-3)-2(2x-3)

We multiply parentheses

4x-4x-12+6

We add all the numbers together, and all the variables

-6

Back to the equation:

-(-6)



We add all the numbers together, and all the variables

3x+14=0

We move all terms containing x to the left, all other terms to the right

3x=-14

x=-14/3

x=-4+2/3

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