3(x+1)+5(x+1)=64

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Solution for 3(x+1)+5(x+1)=64 equation:


Simplifying
3(x + 1) + 5(x + 1) = 64

Reorder the terms:
3(1 + x) + 5(x + 1) = 64
(1 * 3 + x * 3) + 5(x + 1) = 64
(3 + 3x) + 5(x + 1) = 64

Reorder the terms:
3 + 3x + 5(1 + x) = 64
3 + 3x + (1 * 5 + x * 5) = 64
3 + 3x + (5 + 5x) = 64

Reorder the terms:
3 + 5 + 3x + 5x = 64

Combine like terms: 3 + 5 = 8
8 + 3x + 5x = 64

Combine like terms: 3x + 5x = 8x
8 + 8x = 64

Solving
8 + 8x = 64

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 8x = 64 + -8

Combine like terms: 8 + -8 = 0
0 + 8x = 64 + -8
8x = 64 + -8

Combine like terms: 64 + -8 = 56
8x = 56

Divide each side by '8'.
x = 7

Simplifying
x = 7

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