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3(x+1)+4x=6x-3
We move all terms to the left:
3(x+1)+4x-(6x-3)=0
We add all the numbers together, and all the variables
4x+3(x+1)-(6x-3)=0
We multiply parentheses
4x+3x-(6x-3)+3=0
We get rid of parentheses
4x+3x-6x+3+3=0
We add all the numbers together, and all the variables
x+6=0
We move all terms containing x to the left, all other terms to the right
x=-6
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