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3(x+1)+4(2x-1)=5(2x+7)
We move all terms to the left:
3(x+1)+4(2x-1)-(5(2x+7))=0
We multiply parentheses
3x+8x-(5(2x+7))+3-4=0
We calculate terms in parentheses: -(5(2x+7)), so:We add all the numbers together, and all the variables
5(2x+7)
We multiply parentheses
10x+35
Back to the equation:
-(10x+35)
11x-(10x+35)-1=0
We get rid of parentheses
11x-10x-35-1=0
We add all the numbers together, and all the variables
x-36=0
We move all terms containing x to the left, all other terms to the right
x=36
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