3(x+1)+3=x+2(x-3)+11

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Solution for 3(x+1)+3=x+2(x-3)+11 equation: 



3(x+1)+3=x+2(x-3)+11

We move all terms to the left:

3(x+1)+3-(x+2(x-3)+11)=0

We multiply parentheses

3x-(x+2(x-3)+11)+3+3=0



We calculate terms in parentheses: -(x+2(x-3)+11), so:

x+2(x-3)+11

We multiply parentheses

x+2x-6+11

We add all the numbers together, and all the variables

3x+5

Back to the equation:

-(3x+5)



We add all the numbers together, and all the variables

3x-(3x+5)+6=0

We get rid of parentheses

3x-3x-5+6=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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