3(x+1)+3=7(x-2)

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Solution for 3(x+1)+3=7(x-2) equation: 



3(x+1)+3=7(x-2)

We move all terms to the left:

3(x+1)+3-(7(x-2))=0

We multiply parentheses

3x-(7(x-2))+3+3=0



We calculate terms in parentheses: -(7(x-2)), so:

7(x-2)

We multiply parentheses

7x-14

Back to the equation:

-(7x-14)



We add all the numbers together, and all the variables

3x-(7x-14)+6=0

We get rid of parentheses

3x-7x+14+6=0

We add all the numbers together, and all the variables

-4x+20=0

We move all terms containing x to the left, all other terms to the right

-4x=-20

x=-20/-4

x=+5

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