3(x+1)+2=6x-3(-3+x)

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Solution for 3(x+1)+2=6x-3(-3+x) equation:



3(x+1)+2=6x-3(-3+x)
We move all terms to the left:
3(x+1)+2-(6x-3(-3+x))=0
We add all the numbers together, and all the variables
3(x+1)-(6x-3(x-3))+2=0
We multiply parentheses
3x-(6x-3(x-3))+3+2=0
We calculate terms in parentheses: -(6x-3(x-3)), so:
6x-3(x-3)
We multiply parentheses
6x-3x+9
We add all the numbers together, and all the variables
3x+9
Back to the equation:
-(3x+9)
We add all the numbers together, and all the variables
3x-(3x+9)+5=0
We get rid of parentheses
3x-3x-9+5=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation

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