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3(x+1)+2=5x-2(-2+x)
We move all terms to the left:
3(x+1)+2-(5x-2(-2+x))=0
We add all the numbers together, and all the variables
3(x+1)-(5x-2(x-2))+2=0
We multiply parentheses
3x-(5x-2(x-2))+3+2=0
We calculate terms in parentheses: -(5x-2(x-2)), so:We add all the numbers together, and all the variables
5x-2(x-2)
We multiply parentheses
5x-2x+4
We add all the numbers together, and all the variables
3x+4
Back to the equation:
-(3x+4)
3x-(3x+4)+5=0
We get rid of parentheses
3x-3x-4+5=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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