3(x+1)+1=x+2(x+2)

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Solution for 3(x+1)+1=x+2(x+2) equation: 


Simplifying
3(x + 1) + 1 = x + 2(x + 2)

Reorder the terms:
3(1 + x) + 1 = x + 2(x + 2)
(1 * 3 + x * 3) + 1 = x + 2(x + 2)
(3 + 3x) + 1 = x + 2(x + 2)

Reorder the terms:
3 + 1 + 3x = x + 2(x + 2)

Combine like terms: 3 + 1 = 4
4 + 3x = x + 2(x + 2)

Reorder the terms:
4 + 3x = x + 2(2 + x)
4 + 3x = x + (2 * 2 + x * 2)
4 + 3x = x + (4 + 2x)

Reorder the terms:
4 + 3x = 4 + x + 2x

Combine like terms: x + 2x = 3x
4 + 3x = 4 + 3x

Add '-4' to each side of the equation.
4 + -4 + 3x = 4 + -4 + 3x

Combine like terms: 4 + -4 = 0
0 + 3x = 4 + -4 + 3x
3x = 4 + -4 + 3x

Combine like terms: 4 + -4 = 0
3x = 0 + 3x
3x = 3x

Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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