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3(x+1)+11x=2(4+5x)+3
We move all terms to the left:
3(x+1)+11x-(2(4+5x)+3)=0
We add all the numbers together, and all the variables
3(x+1)+11x-(2(5x+4)+3)=0
We add all the numbers together, and all the variables
11x+3(x+1)-(2(5x+4)+3)=0
We multiply parentheses
11x+3x-(2(5x+4)+3)+3=0
We calculate terms in parentheses: -(2(5x+4)+3), so:We add all the numbers together, and all the variables
2(5x+4)+3
We multiply parentheses
10x+8+3
We add all the numbers together, and all the variables
10x+11
Back to the equation:
-(10x+11)
14x-(10x+11)+3=0
We get rid of parentheses
14x-10x-11+3=0
We add all the numbers together, and all the variables
4x-8=0
We move all terms containing x to the left, all other terms to the right
4x=8
x=8/4
x=2
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